y=(3/x^2+2)

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Solution for y=(3/x^2+2) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

y = 3/(x^2)+2 // - 3/(x^2)+2

y-(3/(x^2))-2 = 0

y-3*x^-2-2 = 0

-3*x^-2 = -(y-2) // : -3

x^-2 = (2-y)/(-3)

-2 < 0

1/(x^2) = (2-y)/(-3) // * x^2

1 = x^2*((2-y)/(-3)) // : (2-y)/(-3)

-3*(2-y)^-1 = x^2

x^2 = -3*(2-y)^-1 // ^ 1/2

abs(x) = (-3)^(1/2)*(2-y)^(-1/2)

x = (-3)^(1/2)*(2-y)^(-1/2) or x = -((-3)^(1/2)*(2-y)^(-1/2))

x in { (-3)^(1/2)*(2-y)^(-1/2), -((-3)^(1/2)*(2-y)^(-1/2)) }

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